Is it possible to implement agents, GenerativeAgent wit...

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The community member asked if it is possible to implement agents, GenerativeAgent without an OpenAI API key. Based on the comments, it appears that an OpenAI API key is required to use the OpenAIAgent implementation in LlamaIndex. The API key is necessary for the agent to authenticate requests to OpenAI's API and function as expected. The comments provide examples of how to set the API key, either globally or at a per-instance level. Without the API key, the agent would not be able to make requests to OpenAI's API and would not function as intended.

MMatthews

@kapa.ai Is it possible to implement agents, GenerativeAgent without OPENAI Key?

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kkapa.ai

Please stand by @Matthews as I search the knowledge base. I normally take about 20 seconds or so. :wave:

kkapa.ai

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Based on the information provided in the extracts, it appears that an OpenAI API key is required to use the OpenAIAgent implementation in LlamaIndex. The OpenAI API key is used to authenticate requests to OpenAI's API, which is necessary for the agent to function.

Here is an example of how to provide the OpenAI API key:

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import openai

OPENAI_API_KEY = getpass.getpass("OpenAI API Key:")
openai.api_key = OPENAI_API_KEY

(Source: GitHub ())

You can also set the API key at a per-instance level:

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from llama_index.llms import OpenAI

llm = OpenAI(model="text-davinci-003", api_key="BAD_KEY")
resp = OpenAI().complete("Paul Graham is ")
print(resp)

(Source: GitHub ())

Without the OpenAI API key, the agent would not be able to make requests to OpenAI's API and therefore would not function as expected.
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Is it possible to implement agents, GenerativeAgent without OPENAI Key?